{"id":1136,"date":"2017-10-19T02:19:20","date_gmt":"2017-10-19T06:19:20","guid":{"rendered":"http:\/\/blog.richmond.edu\/math320\/?p=1136"},"modified":"2017-10-19T02:19:20","modified_gmt":"2017-10-19T06:19:20","slug":"muddiest-point-101217","status":"publish","type":"post","link":"https:\/\/blog.richmond.edu\/math320\/2017\/10\/19\/muddiest-point-101217\/","title":{"rendered":"Muddiest Point 10\/12\/17"},"content":{"rendered":"<p>One of the things we did in this class was introduce and go through the proof for Theorem 4.2.3 (Sequential Criterion for Functional Limits). The theorem states: Given a function <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%3AA+%5Crightarrow+%5Cmathbb+R&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f:A &#92;rightarrow &#92;mathbb R\" class=\"latex\" \/> and <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=c+%5Cin+L%28A%29&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"c &#92;in L(A)\" class=\"latex\" \/>, the following are equivalent:<\/p>\n<p>i.) <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=lim_%7Bx+%5Cto+c%7D+f%28x%29%3DL&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"lim_{x &#92;to c} f(x)=L\" class=\"latex\" \/><\/p>\n<p>ii.)<img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cforall&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;forall\" class=\"latex\" \/> sequences <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%28x_n%29+%5Csubset+A&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"(x_n) &#92;subset A\" class=\"latex\" \/> such that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=x_n+%5Cneq+c&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"x_n &#92;neq c\" class=\"latex\" \/> and <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%28x_n%29+%5Crightarrow+c%2C&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"(x_n) &#92;rightarrow c,\" class=\"latex\" \/> it follows that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%28f%28x_n%29%29+%5Crightarrow+L.&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"(f(x_n)) &#92;rightarrow L.\" class=\"latex\" \/> For me, I think that the muddiest point lies in fully understanding the logic in the proof.<\/p>\n<p>For me, I think that the muddiest point lies in fully understanding the logic in the proof, so I&#8217;m going to go through the intuition needed to understand the proof. For the <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5CRightarrow&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;Rightarrow\" class=\"latex\" \/> direction of the proof, we assume part i and prove part ii by using the topological definition of a function limit. We start with <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cvarepsilon+%3E0&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;varepsilon &gt;0\" class=\"latex\" \/>, and then say that there exists a <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=V_%5Cdelta+%28c%29&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"V_&#92;delta (c)\" class=\"latex\" \/> that contains all x&#8217;s that are not equivalent to c. From the definition, it follows that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x%29+%5Cin+V_%5Cvarepsilon+%28L%29.&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x) &#92;in V_&#92;varepsilon (L).\" class=\"latex\" \/> At this point, it is important to distinguish what we still need to show. We want to show that\u00a0<img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x_n%29+%5Cin+V_%5Cvarepsilon+%28L%29%2C&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x_n) &#92;in V_&#92;varepsilon (L),\" class=\"latex\" \/> so we can see that in order to bridge the gap between\u00a0what we have and what we want, we need N for which the statement is true with <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=n+%5Cgeq+N&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"n &#92;geq N\" class=\"latex\" \/> so that\u00a0<img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x_n%29+%5Cin+V_%5Cvarepsilon+%28L%29&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x_n) &#92;in V_&#92;varepsilon (L)\" class=\"latex\" \/> is true.<\/p>\n<p>The other direction of the proof is a proof by contraposition. We assume that ii is true and negate i, so it says $latex\u00a0lim_{x \\to c} f(x) \\neq L.$ Now, we can use the topological definition of a functional limit to help us here. From the negation of ii, we know that there exists a <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cvarepsilon_o+%3E0&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;varepsilon_o &gt;0\" class=\"latex\" \/> such that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cforall+%5Cdelta+%3E0%2C&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;forall &#92;delta &gt;0,\" class=\"latex\" \/> <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cexists+x+%5Cin+V_%5Cdelta+%28c%29+%5Csetminus+%5C%7Bc%5C%7D&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;exists x &#92;in V_&#92;delta (c) &#92;setminus &#92;{c&#92;}\" class=\"latex\" \/> such that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x%29+%5Cnotin+V_%7B%5Cvarepsilon_o%7D+%28L%29.&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x) &#92;notin V_{&#92;varepsilon_o} (L).\" class=\"latex\" \/> Since we want to contradict our negation, we proceed by picking a specific <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=%5Cdelta&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"&#92;delta\" class=\"latex\" \/> and a point <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=x_n&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"x_n\" class=\"latex\" \/>. These are used to show that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x_n%29+%5Cnotin+V_%7B%5Cvarepsilon_o%7D+%28L%29.&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x_n) &#92;notin V_{&#92;varepsilon_o} (L).\" class=\"latex\" \/> However, this means that <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=x_n+%5Cneq+c%2C&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"x_n &#92;neq c,\" class=\"latex\" \/> so <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=f%28x_n%29&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"f(x_n)\" class=\"latex\" \/> does not converge to <img decoding=\"async\" src=\"https:\/\/s0.wp.com\/latex.php?latex=L.&#038;bg=ffffff&#038;fg=000&#038;s=0&#038;c=20201002\" alt=\"L.\" class=\"latex\" \/> This contradicts ii, which was assumed to be true, so we see that i holds to be true.<\/p>\n<p>Overall, the proof of Theorem 4.2.3 is easier to complete when the topological definition of a function limit is fully understood. Also, I found that the graph on the top of page 116 in the book especially useful when trying to visualize what is happening with the proof.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>One of the things we did in this class was introduce and go through the proof for Theorem 4.2.3 (Sequential Criterion for Functional Limits). The theorem states: Given a function and , the following are equivalent: i.) ii.) sequences such that and it follows that For me, I think that the muddiest point lies in [&hellip;]<\/p>\n","protected":false},"author":2206,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2}},"categories":[58822],"tags":[],"class_list":["post-1136","post","type-post","status-publish","format-standard","hentry","category-muddiest-point"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p7L4E1-ik","jetpack-related-posts":[],"_links":{"self":[{"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/posts\/1136","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/users\/2206"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/comments?post=1136"}],"version-history":[{"count":0,"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/posts\/1136\/revisions"}],"wp:attachment":[{"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/media?parent=1136"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/categories?post=1136"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.richmond.edu\/math320\/wp-json\/wp\/v2\/tags?post=1136"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}